Acceptance-Rejection Sampling

This method generates random vectors ${\bf y}_i$ with normally distributed random components, and estimates $P({\bf b})$ using

\begin{displaymath}\bar{P} = \frac{1}{N}\sum_{j=1}^N R(C{\bf y}_j)),
\end{displaymath}

where

\begin{displaymath}R({\bf x}) = \left\{ \begin{array}{cl}
1 & x_i \leq b_i \mbo...
... 1 \leq i \leq m \\
0 & \mbox{otherwise} \end{array}.
\right.
\end{displaymath}

Deák explains that in this case a standard error estimate is given by $E = \sqrt{\bar{P}(1-\bar{P})/N}$. Because $E < 0.5/\sqrt{N}$, at least one decimal digit of absolute accuracy is expected with probability 0.95 when N = 100.



Alan C Genz
1999-10-21